Cannot open index with Luke

Hibernate Search
1

I want to open indexed file with Luke , But I have this error log.

Cannot open index path D:\data\hch\entity.myEntity. Not a valid lucene index directory or corrupted?

I try with all Directory Implementation options, But I still have this error.

Os: windows 7
Hibernate search: 5.9.2.Final

Hibernate Search Config:

setProperty("hibernate.search.default.directory_provider", "filesystem");
setProperty("hibernate.search.default.indexBase", "/data/hch");
setProperty("hibernate.search.Rules.directory_provider", "filesystem");
setProperty("hibernate.search.jmx_enabled", "true");
setProperty("hibernate.search.generate_statistics", "true");
2

All I can tell you is that it should work with the default options of Luke. Maybe just enable “read-only”, and double-check you are selecting the right directory. I know the GUI used to be really disturbing; if I remember correctly you had to first select the parent directory, then the index directory, then click “OK”.

3

Luke version was incompatible with apache lucene version that used in my project. I tried with other Luke versions, the problem solved.

4

I am using lucene 5.5.4 and luke v8.0.0
i am facing same issue. will you please suggest luke version for lucene 5.4.4
and also from where to download luke

5

Please try with versions under 6.
Link

6

Have you tried turning on read-only mode?

7

I tried this route to no avail, including using past, and present versions. I downloaded the Lucene binary. Within the bin dir, there’s luke.cmd or luke.sh. It worked for me!